Verified Answer :

konrad509

\(-3(4v+1)-3(2v+3) =\\ -12v-3-6v-9=\\ -18v-12\)

First you have to multiply the numbers out of the paranthesis, with the numbers in it:
\(-3(4v+1)-3(2v+3)\\ -3\cdot 4v-3\cdot 1-3\cdot 2v-3\cdot 3\) 
then solve :
\(-12v-3-6v-9\\ -18v-12\)

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