In a 45°-45°-90° triangle, the length of the hypotenuse is 11. Find the length of one of the legs
Answer:
7.78 or \(\frac{11}{\sqrt{2} }\)
Step-by-step explanation:
here we are given a right angle triangle , and in a right triangle , sum of squares of sides is equal to the square of hypotenuse.
\(a^2+b^2=c^2\)
This is right angle scalene triangle as the two angles other than right angle are 45° each.
Hence ,
in this case we have
\(a^2+a^2=c^2\)
\(2a^2=c^2\)
\(a^2=\frac{c^2}{2}\)
Taking square roots on both sides
\(a=\frac{c}{\sqrt{2}}\)
Here we have hypotenuse c given as 11
hence
\(a=\frac{11}{\sqrt{2}}\)
Answer