\(xy=24\)
\(x+y=-14\)
Squaring both sides of the second equation we get
\((x+y)^2=196\)
\(x^2+y^2+2xy=196\)
But xy = 24,
\(x^2+y^2+48=196\)
\(x^2+y^2=148\)
Subtract 2xy from both sides
But -2xy=-48
\(x^2+y^2-2xy=148-48\)
\((x-y)^2=100\)
\(x-y=100\)
If x + y = -14 and x - y = 100
then x = 43 and y = - 57.
Please mark me as brainliest.
