How to find the limit of that question
Factor the numerator using difference of cubes:\(a^3 - b^3 = (a-b)(a^2 +ab+b^2)\)a = xb = 2\(\frac{x^3 - 8}{x-2} = \frac{(x-2)(x^2 +2x+4)}{x-2} = x^2 +2x+4\)Now you can evaluate limit as x=2.\(\lim_{x \to 2} (x^2 +2x+4) = 2^2 +2(2)+4 = 12\)
