A 1250 kg car is stopped at a traffic light. A 3550 kg truck moving at 8.33 m/s hits the car from behind If bumpers lock,how fast will the two vehicles move?
1,250 kg + 3,550 kg = 4,800 kg combined
(1,250 kg)(0 ) +
(3,550 kg)(8.33 ) = (4,800 kg)(v)
v = 6.16
answer 6.6m/s
The momentum can be defined by the product of the maas and velocity. The final velocity of the trucks after the collision is 6.6 m/s.
\(m_1v_1 +m_2v_2 = (m_1+m_2)v_f\)
Where,
\(m_1\)= mass of 1st truck = 1250 kg
\(m_2\) - mass of second truck = 3550 kg
\(v_1\) - velocity of the first truck = 0 m\s
\(v_2\) - velocity of the second truck = 8.33 m/s
\(v_f\) - final velocity after collision
Put the values in the formula,
\(1250 \times 0+(1350 \times 8.33 ) = (1250+1350 )v_f \\\\v_f = 6.6\rm \ m/s\)
Therefore, the final velocity of the trucks after the collision is 6.6 m/s.
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