During a construction project, heavy rain filled construction cones with water. The diameter of a cone is 12 in. and the height is 27 in. What is the volume of the water that filled one cone?
volume of a cone = πr^2(h/3)
r=6
h=27
v = π(6^2)27/3
v = π (36)(9)
v=π324 in. cubed
or
v=1,017.36 in. cubed
Answer:
the volume of the water that filled one cone is 1017.36 in³ approximately
Step-by-step explanation:
To find the volume of water that filled the a cone, we will use the formula;
V = π r² \(\frac{h}{3}\)
π is a constant
r is the radius of the cone
h is the height
V = volume of the cone.
From the question given;
Diameter of a cone is 12 in., but radius id half of diameter, this implies r=d/2 = 12/2 = 6 in.
h = 27 and π≈3.14
We can now proceed to insert the values into the formula;
V = π r² \(\frac{h}{3}\)
≈ 3.14 × (6)² × \(\frac{27}{3}\)
≈ 3.14×36×9
≈1017.36 in³
Therefore the volume of the water that filled one cone is 1017.36 in³ approximately