Write the equation of a line that is perpendicular to the given line and that passes through the given point 2x+9y=-30;(-8,0)
y=(-30-2x)/9 the slop is -2/9 because perpendicular to the given line so the new slop is 9/2
y=9/2x+b
0=9/2*-8+b
0=-36+b
b=36
y=9/2x+36 is the answer
Answer:
\(y=\frac{9}{2}x+36\)
Step-by-step explanation:
The given equation is 2x+9y=-30.
Subtracting 2x both sides :
9y=-2x-30
Dividing both sides by 9 we have:
\(y=\frac{-2}{9}x -\frac{10}{3}\)
This equation is of the form y=mx+b where the slope m=\(\frac{-2}{9}\)
Slope of a perpendicular line =\(\frac{9}{2}\)
The perpendicular line passes through the point (-8,0)
The equation of the perpendicular line is :\(y-0=\frac{9}{2} (x+8)\)
Or \(y=\frac{9}{2}x+36\)