A non-scale model of the earth has a diameter of 18 in. Within an outer clay layer, there is a core made of a ball with a diameter of 3 in.


What is the volume of the clay?


Use 3.14 to approximate pi. Round to the nearest hundredth if necessary.

_______cm^3

Verified Answer :

Answer: \(3037.95\ cm^3\)

Step-by-step explanation:

We know that the volume of sphere is given by :-

\(\text{Volume}=\frac{4}{3}\pi r^3\), where r is the radius of sphere.

Given : Diameter of non-scale model of the earth= 18 in.

Radius = \(\frac{18}{2}=9\ in.\)

We know that the volume of non-scale model of the earthis given by :-

\(\text{Volume}=\frac{4}{3}\pi (9)^3\\\\\Rightarrow\ \text{Volume}=\frac{4}{3}(3.14)(729)\\\\\Rightarrow\ \text{Volume}=3052.08\ cm^3\)

Diameter of ball= 3 in.

Radius = \(\frac{3}{2}\ in.\)

We know that the volume of ball is given by :-

\(\text{Volume}=\frac{4}{3}\pi (\frac{3}{2})^3\\\\\Rightarrow\ \text{Volume}=\frac{4}{3}(3.14)(\frac{27}{8})\\\\\Rightarrow\ \text{Volume}=14.13\ cm^3\)

The volume of the clay= \(3052.08\ cm^3-14.13\ cm^3=3037.95\ cm^3\)

The volume of the clay is 3037.95 IN^3.

What is the volume of the clay?

The volume of the clay = volume of the earth - volume of the core ball

Volume of a sphere = 4/3 x pi x r^3

Where:

  • pi = 3.14
  • r = radius = diameter / 2

  • Volume of the earth = 4/3 x 3.14 x (18/2)^3 = 3052.08 in^3
  • Volume of the ball =  4/3 x 3.14 x (3/2)^3 = 14.14 in^3
  • Volume of the clay =  3052.08 in^3 -  14.14 in^3 = 3037.95 IN^3

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