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Gator47 Gator47
  • 08-02-2017
  • Chemistry
Answered

What mass of water is needed to react with 98.7g of Li3N

Verified Answer :

piggy4703
piggy4703 piggy4703
  • 08-02-2017

moles Li3N = 98.7 g/34.8297 g/mol=2.83 

the ratio between Li3N and H2O is 1 : 3 
moles water neeeded = 2.83 x 3=8.49 
mass water = 8.49 mol x 18.02 g/mol=153.0 g 

moles NH3 produced = 2.83 
molescules of NH3 = 2.83 x 6.02 x 10^23=1.70 x 10^24 

moles NH3 (STP) = 45.0/22.4 =2.0 
moles Li3N = 2.0 
mass Li3N = 2.0 x 34.8297 g/mol=69.6 g

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