Subtract 8x from both sides to get \(x^{2} -8x+20=0\) Then using the quadratic formula: \(x= \frac{-b+/- \sqrt{ b^{2}-4ac } }{2a}\) Substitute a = 1, b = -8, and c = 20 \(x= \frac{8+/- \sqrt{64-4(1)(20)} }{2(1)}\) -(-8) = 8 and (-8)^2 = 64 \(x=4+/-2i\)
