If |2w - 3| > 5
then
2w - 3 < - 5 or 2w - 3 > 5
2w < - 5 + 3 or 2w > 5 + 3
2w < - 2 or 2w > 8
w < -2/2 or w > 8/2
w < -1 or w > 4
So the solution set is
S = { x E R : w < -1 or w > 4}
or using the interval notation
S = (- infinity, -1) U (4, + infinity).
I hope this helps. =)
