ashheart12
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The base of a solid oblique pyramid is an equilateral triangle with a base edge length of 14 units.

What is BC, the height of the pyramid?

7 units

7 sqrt2 units

14 units

14 sqrt2 units

The base of a solid oblique pyramid is an equilateral triangle with a base edge length of 14 units. What is BC, the height of the pyramid? 7 units 7 sqrt2 units class=

Verified Answer :

MissPhiladelphia

In order to solve this problem, we need our knowledge on trigonometric functions and use it here to determine the height. We see that a right triangle is being formed where the height is involved. We calculate as follows:

tan 45 = opposite side / adjacent side
tan45 = height / 14
height = 14 square units

Third option is the correct answer.

ogorwyne

The height of the pyramid BC is equal to 14 units.

We have a right angled triangle BAC

Using the trigonometric formula

\(tangent = \frac{opposite}{adjacent}\)

The tangent here = 45°

The opposite side, h (this is the side that is facing the angle)

The adjacent = 14°

This is due to the fact AD=DC=AC

When we put the values into the formula:

\(Tan45=\frac{h}{14}\)

Tan 45= 1

  • When we cross multiply,

14*1 = h

Therefore the height of the pyramid BC is 14 units.

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