Data:
\(\frac{2}{3}\:cup\:of\:soup\longrightarrow\:1\:(each\:bowl)\)
\(40\:cups\:of\:soup\longrightarrow\:?\:(each\:bowl)\)
Solving: (They are proportional measures, the rule of three is made (directly proportional)
\(\frac{ \frac{2}{3}}{40} = \frac{1}{y}\)
multiply cross
\(\frac{2}{3}*y = 40*1\)
\(\frac{2y}{3} = 40\)
multiply cross
\(2y = 3*40\)
\(2y = 120\)
\(y = \frac{120}{2}\)
\(\boxed{\boxed{y =60\:bowls}}\end{array}}\qquad\quad\checkmark\)
