Answer:
\(=-2t^2+18t+9\)
Step-by-step explanation:
the expression we have is:
\((3t-3)+(6t^2+4t+13)+(-8t^2+11t-1)\)
the first step is to get rid of the parentheses:
\(3t-3+6t^2+4t+13-8t^2+11t-1\)
an now, we put the like terms together, this will be subtract
\(6t^2-8t^2\), and the result is \(-2t^2\)
and then add:
\(3t+4t+11t\) which results in \(18t\)
and finally add all the independent numbers:
\(-3+13-1\) which is equal to \(9\)
so the total result is:
\((3t-3)+(6t^2+4t+13)+(-8t^2+11t-1)\)\(=-2t^2+18t+9\)
