A water pump with a power of 3.4 × 102 watts lifts water at the rate of 7.5 × 10-2 meters/second from a water tank. What is the force exerted by the pump on the water?
Power = force x velocity
3.4 x 10^2 = force x 7.5 x 10^-2
Force = 3.4 x 10^2
--------------------
7.5 x 10^-2
= 4533.33 N
Hope this helps!!
Answer : The force exerted by the pump on the water is, 4533.33 N
Solution :
Power : It is defined as the work done in per unit time.
Formula used :
\(P=F\times V\\\\F=\frac{P}{V}\)
where,
P = power = \(3.4\times 10^2watts\)
V = velocity = \(7.5\times 10^{-2}m/s\)
F = force
Now put all the given values in the above formula, we get the force exerted by the pump on water.
\(F=\frac{3.4\times 10^2watts}{7.5\times 10^{-2}m/s}=4533.33N\)
Therefore, the force exerted by the pump on the water is, 4533.33 N