ehercul
Answered

A water pump with a power of 3.4 × 102 watts lifts water at the rate of 7.5 × 10-2 meters/second from a water tank. What is the force exerted by the pump on the water?

Verified Answer :

Power = force x velocity
   3.4 x 10^2 = force x 7.5 x 10^-2

Force = 3.4 x 10^2 
              --------------------
               7.5 x 10^-2 
 
           =      4533.33 N

Hope this helps!!

Answer : The force exerted by the pump on the water is, 4533.33 N

Solution :

Power : It is defined as the work done in per unit time.

Formula used :

\(P=F\times V\\\\F=\frac{P}{V}\)

where,

P = power = \(3.4\times 10^2watts\)

V = velocity = \(7.5\times 10^{-2}m/s\)

F = force

Now put all the given values in the above formula, we get the force exerted by the pump on water.

\(F=\frac{3.4\times 10^2watts}{7.5\times 10^{-2}m/s}=4533.33N\)

Therefore, the force exerted by the pump on the water is, 4533.33 N