Answer: The pressure of an ideal gas 0.278 atm.
Explanation:
Volume of the ideal gas ,V = 35.5 L
Pressure of an ideal gas,P = 0.138 atm
Temperature of an ideal gas = 223 K
Number of moles of an ideal gas = 0.540 mol
Ideal gas equation is given as:
\(PV=nRT\)
\(P=\frac{n}{V}\times RT=\frac{0.540 mol}{35.5 L}\times 0.0820 atm l/mol K\times 223 K\)
P = 0.278 atm
The pressure of an ideal gas 0.278 atm.
