(2n + 1) (n - 2) = 33
Distribute to get2n + 1 + n - 2 = 33Now simplify to get3n -1 = 33Now begin to get the variable by itself by adding 1 to 33 and getting rid of -13n = 34Divide 34 by 334/3 = 1.3(repeating)
(2n+1)(n−2)=33\(2n^{2}\)−3n−2=33subtract 33 from both sides..\(2n^{2}\)−3n−2−33=33−332n2−3n−35=0factor left side of equation...(2n+7)(n−5)=0set factors equal to 0...2n+7=0 or n−5=0n=\(\frac{-7}{2}\) or n=5
