What is the solution of log(t-3)=log(17-4t)?
log=13
t=4
So, this is because they already given you t because the four is on front of it that gives you your value. From there you will proceed to j7st do the math in your parentheses. You should get log=(1) & log=(13) because 1 times anything is that number just use the inverse of each would be eachother. So, 1x13 is the same as 13x1
The solution of log(t-3)=log(17-4t) is t = 4
log(t-3) = log(17-4t)
divide both sides by
\(\frac{log(t-3) }{log(17-4t)} = \frac{log(17-4t)}{log(17-4t)}\)
Therefore,
\(\frac{log(t-3) }{log(17-4t)} = 1\)
\(\frac{(t-3) }{(17-4t)} = 1\)
cross multiply
t - 3 = 17 - 4t
t + 4t = 17 + 3
5t = 20
t = 20 / 5
t = 4
learn more on logarithm here: https://brainly.com/question/10060764