Please help!! How do I do this? I don't understand the question. I'll write it out since I can't upload a pic for some reason.

For each of the situations, state the method you would use to solve ax^2+bx+c=0. Explain your choice

Ab^2-4ac>0
Bb^2-4ac=0
Cb^2-4ac<0

when b^2 -4ac >0 you get rational answers. I suppose you could use factoring as well as the quadratic formula.
when b^2 -4ac =0 You get one answer. Okay it is till technically "two" answers but you say BOTH values of x = whatever.
when b^2 -4ac <0 the answers are complex (imaginary) and have the value of "i" somewhere in them. For example the answers might be 2 + 2i that kind of thing

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Please help!! How do I do this? I don't understand the question. I'll write it out since I can't upload a pic for some reason. For each of the situations, state the method you would use to solve ax^2+bx+c=0. Explain your choice Ab^2-4ac>0Bb^2-4ac=0Cb^2-4ac<0

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Please help!! How do I do this? I don't understand the question. I'll write it out since I can't upload a pic for some reason.

For each of the situations, state the method you would use to solve ax^2+bx+c=0. Explain your choice

Ab^2-4ac>0
Bb^2-4ac=0
Cb^2-4ac<0