radomes.openskiesproject.org
kcmaese kcmaese
  • 06-02-2017
  • Mathematics
Answered

how to solve 8x^3-27=0

Verified Answer :

alexisfleming60
alexisfleming60 alexisfleming60
  • 06-02-2017

Factor using difference of cubes, and set each factor equal to 0.
x=(-3+3i\sqrt(3))/(4),(-3-3i\sqrt(3))/(4),(3)/(2)

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mohamedjamal
mohamedjamal mohamedjamal
  • 06-02-2017

8x³-27=0
8x³=27
x³=27/8
x=∛27/∛8
x=3/2

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