Kalon and his friend Marna own a chimney sweep service company. Working together, they can clean a chimney in 1 5/7 hours. If it takes Kalon 4 hours to clean a 20-foot chimney by himself, how long does it take Marna to clean the same size chimney by herself?

Verified Answer :

Kalon + Marna = 12/7 hours working together
( I attached two formulas. Use formula 3)

Worker 2 Time = (worker 1 Time) Total Time /  [(worker 1 Time) - Total Time]
Worker 2 Time = ((4)
12/7) /  [4 - 12/7]
Worker 2 Time =



6.8571428571



/



2.2857142857




Worker 2 Time =

3 hours

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View image wolf1728

Answer:

Step-by-step explanation:

Given that Kalon and his friend Marna own a chimney sweep service company. Working together, they can clean a chimney in 1 5/7 hours and it takes Kalon 4 hours to clean a 20-foot chimney by himself.

i.e. Kalon can do in one hour 1/4 of the work

Marna can do in one hour 1/x of the work

(assuming total x hours Marns taes to clean the same size chimney)

Together they clean

\(\frac{7}{12}\)

\(\frac{1}{4} +\frac{1}{x} =\frac{7}{12}\)

Simplify to get

\(12(x+4)=28x\\3x+12=7x\\4x=12\\x=3\)

Marna takes 3 hours to clean the same size chimney