What is the current in a wire if 3.4•10 to the 19 electrons pass by a point in this wire every 60 seconds
1.6 x 10^19 electrons per coulomb
current (amperes) is defined as the number of coulombs per sec flow
amps = #of electrons /( electrons per coulomb) / 60 sec
= 3.4 x 10^19 electrons /1.6 x 10^19 electrons per coulomb /60 sec
= .035 amps
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Answer : I = 0.0906 A.
Explanation :
It is given that,
No of electrons flowing in a wire, \(q=3.4\times 10^{19}\)
We know that the charge on an electron is given by, \(q_e=1.6\times 10^{-19}\ C\)
So the total charge becomes:
\(q=3.4\times 10^{19}\times 1.6\times 10^{-19}\ C\)
\(q=5.44\ C\)
We know that the current in wire is defined as, \(I=\dfrac{q}{t}\)
\(I=\dfrac{5.44\ C}{60\ s}\)
\(I=0.0906\ A\)
Hence, this is the required solution.