f(x)=x^2-x-12, find f(x)=-12*problem b
Plug in -12 for \(f(x)\)!\(-12=x^{2}-x-12\)Now get the left side equal to zero so you can factor:\(0=x^{2}-x\)Now you can factor out an \(x\)!\(0=x(x-1)\)So for that to equal zero, \(x=0\) or \(x=1\)!
