Verified Answer :
notice, you've got a diameter in inches
and a linear velocity in miles
thus, you'd need to convert first
\(\bf v=rw\implies \cfrac{v}{r}=w\qquad
\begin{cases}
v=\textit{linear speed}\\
r=radius\\
w=\textit{angular speed}\\
--------------\\
v=20\frac{mi}{h}\\
r=\frac{diameter}{2}=\frac{27}{2}
\end{cases}
\\\\
\textit{now, converting 20miles to inches}
\\\\
\cfrac{20mi}{h}\cdot \cfrac{5280ft}{mi}\cdot \cfrac{12in}{ft}\implies \cfrac{20\cdot 5280\cdot 12\ in}{h}\impliedby v
\\\\\\
\cfrac{1267200\frac{in}{h}}{\frac{27}{2}in}=w\)
now, whatever that is, you'll need to divide it by a revolution, recall, a revolution is \(2\pi\)
thus \(\bf \cfrac{\qquad \boxed{\cfrac{1267200\frac{in}{h}}{\frac{27}{2}in}}\qquad }{2\pi }=revolutions\)
Data:
Speed = 20 miles/hour \(\stackrel{converting}{\rightarrow}\) 352 inches/sec
diameter of wheel (length) = 27 inches
Solving:
Dividing the initial speed of 352 inches per second by the length of 27 inches we have:
\(\frac{352\diagup\!\!\!\!\!in/sec}{27\diagup\!\!\!\!\!in} \approx 13.037\:revolutions\:per\:seconds\)
Turning revolutions per second into revolutions per minute, we have:
revolutions per second_____revolutions per minute
1 \(\stackrel{converting}{\longrightarrow}\) 60
13.037 \(\stackrel{converting}{\longrightarrow}\) y
\(\frac{1}{13.037} = \frac{60}{y}\)
multiply cross
\(1*y = 13.037*60\)
\(y = 782.22\to\:\boxed{\boxed{y\approx782\:revolutions\:per\:minute}}\end{array}}\qquad\quad\checkmark\)