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  • 31-01-2015
  • Mathematics
Answered

find the stationary point on the curve y=3x^4 +1 and determine its nature

Verified Answer :

konrad509
konrad509 konrad509
  • 31-01-2015

\(y=3x^4+1\\ y'=12x^3\\\\ 12x^3=0\\ x=0\leftarrow \text{stationary point}\\\\ \forall x\in(-\infty,0)\ y'<0\Rightarrow y\searrow\\ \forall x\in(0,\infty)\ y'>0\Rightarrow y earrow\\ \Downarrow\\ y(0)=y_{min}\)

\(y_{min}=3\cdot0^4+1=1\)

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