31-01-2015
Mathematics

Answered

the curve ax squared - 4x+1 has a stationary point where x equals -3

find the value of a and determine the nature of the stationary point

Verified Answer :

konrad509 konrad509

31-01-2015

\(f(x)=ax^2-4x+1\\ f'(x)=2ax-4\\ 0=2a\cdot(-3)-4\\ 6a=-4\\ a=-\dfrac{4}{6}=-\dfrac{2}{3}\)

It's the quadratic equation where \(a<0\) so the stationary point is a maximum.

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