Solve each system by substitution
Solve each system by substitution
-3x-3y=3
y=-5x-17----------use this to substitute for y
-3x-3(-5x-17)=3----------like this
-3x+15x+51=3-------------combine like terms
12x+51=3------------subtract 51 both sides
12x=-48---------divide by 12 each side to get x by itself
x=-4
y=-5(-4)-17--------------------substitute the -4 for x to find y
y=3
now we plug in both to see if it works:
-3(-4)-3(3)=3--------------We plug in to see if both answers work
12-9=3----------------It works
(-4,3)
Hope this helps :)
\(\left \{ {{-3x-3y=3\:(I)} \atop {y=-5x-17\:(II)}} \right.\)
Replace the equation y in the first equation.
\(-3x-3y=3 (I)\)
\(-3x-3*(-5x-17)=3\)
\(-3x+15x+51=3\)
Now, put the numbers with letter (incognito) to the right and numbers without letter to the left, changing the signal when changing sides.
\(-3x+15x=3-51\)
\(12x = -48\)
\(x = \frac{-48}{12}\)
\(\boxed{\boxed{x = - 4}}\end{array}}\qquad\quad\checkmark\)
Now substitute the found value "x" in the equation y (second equation):
\(y=-5x-17\:(II)\)
\(y = - 5*(-4) - 17\)
\(y = 20 - 17\)
\(\boxed{\boxed{y=3}}\end{array}}\qquad\quad\checkmark\)
Answer:
\(\underline{\textbf{The\:values\\:found\:are:\:X = -4\:and\:
Y = 3} }\)