\(2(x-5)>3x+a \\
2x-10 > 3x+a \\
2x-3x>a+10 \\
-x>a+10 \ \ \ |\times (-1) \\
x<-a-10\)
The solutions must be less than or equal to 5.
\(-a-10 \leq 5 \\
-a \leq 5+10 \\
-a \leq 15 \ \ \ |\times (-1) \\
a \geq -15\)
All the solutions are less than or equal to 5 for a≥-15.