Katy has a bag of yellow and red balls. There are a total of 30 balls in the bag. The probability of drawing a yellow ball is 1/6. How many red balls should be removed from the bag in order to increase the probability to 1/3?


The answer choices are:

a)5

b)9

c)10

d)12

e)15

Verified Answer :

The answer is e)15 Because : to find out the possibility of drawin yellow balls we should divide the number of yellow balls to total balls,
Let y be the number of yellow balls: 
\(\frac { y }{ 30 }\)  and we know that the possibility is equal to \(\frac { 1 }{ 6 }\) 
\(\frac { y }{ 30 } =\frac { 1 }{ 6 }\) from this equation we find y = 5.
If y=5 the number of red balls is 25. If we decrease red balls 15 total number of balls will be = 15. So since number of yellow  balls did not change :\(\frac { 5 }{ 15 } =\frac { 1 }{ 3 }\)