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cano806
cano806 cano806
  • 06-02-2017
  • Mathematics
Answered

what is the equation of the circle with center (-3.2,2.1) and radius 4.3?

Verified Answer :

LammettHash
LammettHash LammettHash
  • 06-02-2017

\((x+3.2)^2+(y-2.1)^2=4.3^2\)

Answer Link
boffeemadrid
boffeemadrid boffeemadrid
  • 06-03-2019

Answer:

\((x+3.2)^2+(y-2.1)^2=(4.3)^2\)

Step-by-step explanation:

It is given that the center of the circle is (-3.2,2.1) and radius is 4.3.

Now, the equation of the circle with center (a,b) and the radius 'r' is represented as:

\((x-a)^2+(y-b)^2=r^2\)

Now, the given center is (-3.2,2.1) and radius is 4.3, thus the equation of the circle becomes,:

\((x-(-3.2))^2+(y-2.1)^2=(4.3)^2\)

\((x+3.2)^2+(y-2.1)^2=(4.3)^2\)

Which is the required equation.

Answer Link

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