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Ethangk98 Ethangk98
  • 06-02-2017
  • Mathematics
Answered

Factor 16x^2 + 16x + 4 completely

A(16x + 4)(x + 1)
B(4x + 2)(4x - 2)
C4(2x + 1)^2

Verified Answer :

texaschic101
texaschic101 texaschic101
  • 06-02-2017

16x^2 + 16x + 4...common factor is 4
4(4x^2 + 4x + 1) =
4(2x + 1)(2x + 1) =
4(2x + 1)^2 <===

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