a force of 6lbs acts on an object with a weight of 35 lbs on earth. determine the objects acceleration. final answer must be 5.52ft/s^2
weight of body = 35 lbs
F = ma
m = F/a = 35/32 ( acceleration = 32 ft/s^2)
m= 1.09
so again using same formula,
a = F/m
a= 6/1.09
a= 5.489
or say, acceleration = 5.5 ft/s^2 !!
Answer:
The acceleration of the object is 5.5 ft/s².
Explanation:
Given that,
Force = 6 lbs
Weight = 35 lbs
We need to calculate the mass
Using newton's second law
\(F = mg\)
\(m =\dfrac{F}{g}\)
Put the value into the formula
\(m= \dfrac{35}{32.2}\)
\(m=1.09\ lb\)
We need to calculate the acceleration
Using newton's second law
\(F = ma\)
Put the value into the formula
\(a =\dfrac{6}{1.09}\)
\(a=5.5\ ft/s^2\)
Hence, The acceleration of the object is 5.5 ft/s².