a force of 6lbs acts on an object with a weight of 35 lbs on earth. determine the objects acceleration. final answer must be 5.52ft/s^2

Verified Answer :

weight of body = 35 lbs
F = ma
m = F/a = 35/32 ( acceleration = 32 ft/s^2)
m= 1.09

so again using same formula,
a = F/m
a= 6/1.09
a= 5.489

or say, acceleration = 5.5 ft/s^2 !!

Answer:

The acceleration of the object is 5.5 ft/s².

Explanation:

Given that,

Force = 6 lbs

Weight = 35 lbs

We need to calculate the mass

Using newton's second law

\(F = mg\)

\(m =\dfrac{F}{g}\)

Put the value into the formula

\(m= \dfrac{35}{32.2}\)

\(m=1.09\ lb\)

We need to calculate the acceleration

Using newton's second law

\(F = ma\)

Put the value into the formula

\(a =\dfrac{6}{1.09}\)

\(a=5.5\ ft/s^2\)

Hence, The acceleration of the object is 5.5 ft/s².