30-01-2015
Mathematics

Answered

What are all relative extrema to

f (x)=×^4-32x+4?

Verified Answer :

konrad509 konrad509

30-01-2015

\(f(x)=x^4-32x+4\\ f'(x)=4x^3-32\\\\ 4x^3-32=0\\ 4(x^3-8)=0\\ x=2\\\\ f(2)=2^4-32\cdot2+4=16-64+4=-44\)

The only extremum is \(-44\) and it's minimum.

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