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annabrooks annabrooks
  • 05-02-2017
  • Mathematics
Answered

Find sec θ if

tan θ = 15/8

and θ terminates in QIII.

Verified Answer :

wolf1728
wolf1728 wolf1728
  • 05-02-2017

tangent = opposite/adjacent
tangent = 15 / 8
If opp = 15 and adj = 8 then
hypotenuse^2 = 15^2 + 8^2
hypotenuse^2 = 225 + 64
hypotenuse^2 = 289
hypotenuse = 17

secant = hypotenuse / adjacent
secant = 17 / 8
secant = 2.125

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