When a number is added to six times its square, the result is twelve. Find the number.
Let's represent our number as x.
x is being added to 6 * x², and it equals 12
\(x + 6x^{2}=12\\6x^{2}+x-12=0\)
Factor:
\(6x^{2}+x-12=0\\(2x+3)(3x-4)=0\)
Solve for x:
\((2x+3)=0\\2x=-3\\x=\frac{-3}{2}\\\\(3x-4)=0\\3x=4\\x=\frac{4}{3}\)
Therefore, x = -3/2 and 4/3.