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izzywaPeacorf izzywaPeacorf
  • 05-02-2017
  • Mathematics
Answered

What are the dimensions of a rectangle that has a perimeter of 74 units and an area of 102 square units?

Verified Answer :

wolf1728
wolf1728 wolf1728
  • 05-02-2017
A2L + 2W = 74
B) L * W = 102

L = 102 / W then substituting this into equation A

A) 204/W + 2W = 74
A) 204 + 2W^2 = 74W
A) 2W^2 -74W + 204 = 0
W = 34 and L = 3  OR
W = 3 and L = 34

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