Verified Answer :

apologiabiology

rembber
\(\sqrt[n]{x^m}=x^\frac{m}{n}\)
and \(\frac{1}{x^m}=x^{-m}\) so

\(\frac{8}{ \sqrt[7]{x^{15}} }= \frac{8}{x^ \frac{15}{7} }=8x^{(\frac{-15}{7})}\)

Answer:

\(8 \cdot x^{-\frac{15}{7}}\)

Step-by-step explanation:

Using exponent rule:

  • \(\sqrt[n]{a^m} = a^{\frac{m}{n}}\)
  • \(a^{-m}=\frac{1}{a^m}\)

Given the radical expression:

\(\frac{8}{\sqrt[7]{x^{15}} }\)

Apply the exponent rule:

\(\frac{8}{x^{\frac{15}{7}} }\)

Again apply the exponent rule:

\(8 \cdot x^{-\frac{15}{7}}\)

Therefore, the radical expression \(\frac{8}{\sqrt[7]{x^{15}} }\) in exponential form is, \(8 \cdot x^{-\frac{15}{7}}\)

Related Questions