I need to know how to solve for the value of x
Hey Katie 4^2x+3 = 1We need to solve for x log(4^2x+3) = log (1)Now take log of (2x +3) * log (4) = log (1)2x + 3 = log(1)/log(4)2x + 3 = 02x = 0 - 32x = -3 x = -3/2I hope that's help !