Hi there...
Solve the system using substitution.
2x + 2y = 38
y = x + 3
We need to solve y = x+ 3 for y
substitute x + 3 for y in 2x + 2y = 38
2x + 2y = 38
Now replace x+3 everywhere there's y
2x + 2(x+3) = 38
2x + 2x + 6 = 38
4x + 6 = 38
4x = 38 - 6
4x = 32
x = 32/4
x = 8
Now, we have the number of x which is gonna help us find y
what we gonna do is replace 8 everywhere we see an x so we find y. Please follow me :)
Substitute 8 for x in y = x + 3
y = 8 + 3
y = 11
Final answer : x = 8 and y = 11
The correct option is A
If you have any further questions about my answer please let me know.
By the way.... I would be happy to help you with the other 10 :)
Good luck !
