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LaceyBunnyHop
LaceyBunnyHop LaceyBunnyHop
  • 04-02-2017
  • Mathematics
Answered

  1. Solve the following system of equations using substitution.

2x+2y=38

Y=x+3


A.(8,11)

B.(4,7)

C.(35/4, 47/4)

D.(-4,-7)

Verified Answer :

pinkmermaid pinkmermaid
  • 04-02-2017

First, make sure you convert both equations into standard form. Your two equations would be 2x+2y=38 and -x+y=3. Then multiply the bottom by 2. So your new equations would be 2x+2y=38 and -2x+2y=6. The x would cancel out and you would continue solving for y. y would equal 11 and then you would plug it back into an original equation. When you plug and solve for x, you would get x=8. So your answer would be (8,11)

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