Find x and the. RS and ST
(3x +1) + (2x -2) = 645x = 65x = 13RS = (3x +1) = (313) +1 = 40ST = (2x -2) = (213) -2 = 24
SOLVING: (According to the image)\(\overline{RS} + \overline{ST} = \overline{RT}\)\((3x+1) + (2x-2)=64\)3x + 1 + 2x - 2 = 643x + 2x = 64 - 1 + 25x = 65\(x = \frac{65}{5}\)\(\boxed{\boxed{x = 13}}\end{array}}\qquad\quad\checkmark\)
