Answer:
\(b=\frac{z(2y+1)}{a(3-4y)}\) for \(a(3-4y)
eq 0\).
Step-by-step explanation:
The given equation is
\(3ab-z=y(4ab+2z)\)
We need to solve the above equation for b.
Using distributive property we get
\(3ab-z=y(4ab)+y(2z)\)
\(3ab-z=4aby+2yz\)
Subtract 4aby from both sides.
\(3ab-z-4aby=2yz\)
Add z on both sides.
\(3ab-4aby=2yz+z\)
Taking out the common factor.
\(ab(3-4y)=z(2y+1)\)
Divide both sides by a(3-4y).
\(b=\frac{z(2y+1)}{a(3-4y)}\)
Therefore the value of b is \(b=\frac{z(2y+1)}{a(3-4y)}\) for \(a(3-4y)
eq 0\).
