There are two jobs you can apply for. the first job pays $22,000 the first year, with raises of $4,000 each year thereafter. the second job pays $26,000 the first year with raises of $2,000 each year thereafter. when would you make as much money in the first job as in the second?

We let the number of years that the two jobs will have the same payment be denoted as t. Equating the wages of these two jobs after t - 1 years will give us an equation of,
22,000 + 4000(t -1) = 26,000 + 2000(t - 1)
The value of t from the generated equation is 3. Therefore, after 3 years the jobs will be paying the same wages.

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JeanaShupp JeanaShupp · Answer 2 · 2019-09-11T01:50:26-04:00

Answer: 3rd year

Step-by-step explanation:

Given : There are two jobs you can apply for.

Let x be the time (in years).

The first job pays $22,000 the first year, with raises of $4,000 each year thereafter.

Then, the amount earned in x years by first job can be written as :-

$y=22000+4000(x-1)$...................(1)

The second job pays $26,000 the first year with raises of $2,000 each year there after.

Then, the amount earned in x years can be written as :-

$y=26000+2000(x-1)$...........................(2)

From equation (1) and (2) , we have

$22000+4000(x-1)=26000+2000(x-1)\\\\\Rightarrow\ 4000(x-1)-2000(x-1)=26000-22000\\\\\Rightarrow\ 2000(x-1)=4000\\\\\Rightarrow\ x-1=\dfrac{4000}{2000}=2\\\\\Rightarrow\ x=2+1=3$

Hence, in 3rd year you would make as much money in the first job as in the second.