Imagine that you are standing on the ground 15 feet away from a flagpole. if the top of the flag is 25 feet high, which equation represents the angle θ your feet make with the top of the flag?
Answer: Hence, the angle of elevation with the top of the flag is 59° and
And the equation would be \(\theta=\tan^{-1}(\dfrac{AB}{BC})\)
Step-by-step explanation:
Since we have given that
Height of top of the flag = 25 feet
Distance of the base of flagpole from the person standing on the ground = 15 feet
We need to find the angle of elevation θ :
Consider ΔABC,
\(\tan \theta=\dfrac{AB}{BC}\\\\\tan\theta=\dfrac{25}{15}\\\\\tan \theta=1.67\\\\\theta=\tan^{-1}(1.67)\\\\\theta=59^\circ\)
Hence, the angle of elevation with the top of the flag is 59°.
And the equation would be
\(\theta=\tan^{-1}(\dfrac{AB}{BC})\)