Complete the factorization of 3x2 – 5x + 2.


Which two factors can be multiplied together to make this trinomial?


(x – 2)

A(x – 1)

B(x + 1)

C(3x – 2)

D(3x + 2)

Verified Answer :

Multiply the first coefficient (3) and the last term (2) to get 3*2 = 6

We need to find two numbers that

a) multiply to 6
AND
b) add to -5 (middle coefficient)

Such two numbers are -3 and -2
-3 times -2 = 6
-3 plus -2 = -5

So we can break up the -5x into -3x-2x and then factor by grouping

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3x^2-5x+2

3x^2-3x-2x+2

(3x^2-3x)+(-2x+2)

3x(x-1)+(-2x+2)

3x(x-1)-2(x-1)

(3x-2)(x-1)

So the two factors are (3x-2) and (x-1)

The answers are A and C

The factor of the equation \(3x^{2} -5x+2 = 0\) is \(x = \frac{3}{2} , 1\).

Multiply the first coefficient 3 and the last term 2 to get 3×2 = 6.

Given ,

Quadratic equation = \(3x^{2} -5x+2\)

We have to find,

The two factors can be multiplied together to make this trinomial .

According to the question,

\(3x^{2} - 5x + 2 = 0\\3x^{2} - 3x-2x+2 = 0\\3x ( x - 1) -2 (x-1) = 0\\(3x-2) (x-1) = 0 \\\)

Then, 3x - 2 = 0

         3x = 2

         \(x = \frac{3}{2}\)

And x - 1 = 0

       x = 1

The factor of the equation \(3x^{2} -5x+2 = 0\) is \(x = \frac{3}{2} , 1\).

Multiply the first coefficient 3 and the last term 2 to get 3×2 = 6.

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