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The seventh grade class is putting on a variety show to raise money. It cost $700 to rent the banquet hall that they are going to use. If they charge $15 for each ticket, how many tickets do they need to sell in order to raise at least $1000

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iloram

just divide $1000 by $15, because $15 times something should equal around $1000.

we get 66.6 repeating, so we'll round it up to 67.

67 tickets at least. (67 × $15 = $1005)

TaeKwonDoIsDead

Since the question is partial, i will assume 2 scenarios:

  • They need to raise 1000 income
  • They need to make 1000 as profit

If $1000 as income:

Each ticket costs $15, so \(\frac{1000}{15} =66.67\) tickets would bring them $1000 income. Fractional ticket is not possible, so rounding gives us 67 tickets as the answer.


If $1000 as profit:

Their cost of renting is $700. We know that @@MATH_TOKEN_1@@.

So, @@MATH_TOKEN_2@@. So, to raise $1700, we need \(\frac{1700}{15} =133.33\) tickets. Fractional ticket is not possible, so rounding gives us 114 tickets as the answer.


ANSWER:

If need to raise atleast $1000 as income, they need to sell 67 tickets.

If need to raise atleast $1000 as profit, they need to sell 114 tickets.

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