Verified Answer :

calculista

Answer:

The answer is the option C

\(1+\frac{2}{5}x\)

Step-by-step explanation:

we have

\(2+\frac{3}{5}x-1-\frac{1}{5}x\)

Group terms

\(2+\frac{3}{5}x-1-\frac{1}{5}x=(\frac{3}{5}x-\frac{1}{5}x)+(2-1)\)

\(=(\frac{2}{5}x)+(1)\)

\(=1+\frac{2}{5}x\)

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