What is the mass,in grams,of 1.20x10^25 atoms of calcium?
Answer:
The mass of calcium in the given number of atoms is 797.2 g.
Explanation:
\(N=n\times N_A\)
N = Number of atoms/molecules
n = Moles of compound
\(N_A\) = Avogadro number = \(6.022\times 10^{23} mol^{-1}\)
We have:
Number calcium atoms = \(N=1.20\times 10^{25}\)
n = moles of calcium = ?
\(n=\frac{N}{N_A}=\frac{1.20\times 10^{25}}{6.022\times 10^{23} mol^{-1}}\)
n = 19.93 mol
Atomic mass of calcium = 40 g/mol
Mass of 19.93 moles of calcium = 40 g/mol × 19.93 mol=797.2 g
The mass of calcium in the given number of atoms is 797.2 g.