Verified Answer :

LammettHash

\(h(x)=(f\circ g)(x)\)
\(\sqrt{x+5}=\sqrt{g(x)+2}\)
\(x+5=g(x)+2\)
\(g(x)=x+3\)

Just to check this is correct:

\((f\circ g)(x)=f(g(x))=f(x+3)=\sqrt{(x+3)+2}=\sqrt{x+5}=h(x)\)

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