The submarine is at a depth of -116 2/7 feet when the scientists detect a signal frequency from the ocean floor. They dive farther down to a depth of -180 4/7 feet to check the signal. The net change in their elevation is_____feet.
Answer: \(-64\frac{2}{7}\text{ feet}\)
Step-by-step explanation:
When the scientists detect a signal frequency from the ocean floor, then the depth of submarine =\(-116\frac{2}{7}\) feet
=\(-\frac{814}{7}\) feet
When they dive farther to check the signal, then the depth of the submarine=\(-180\frac{4}{7}=-\frac{1264}{7}\) feet.
The net change in their elevation =\(-\frac{1264}{7}-(-\frac{814}{7})\)
\(=-\frac{1264}{7}+\frac{814}{7}\\=-\frac{450}{7}=-64\frac{2}{7}\text{ feet}\)